Jee Main
Differential Equations
JEE Main 2023 (Online) 29th January Morning Shift
MCQ+4 / -12023
Let \(y=f(x)\) be the solution of the differential equation \(y(x+1)dx-x^2dy=0,y(1)=e\). Then \(\mathop {\lim }\limits_{x \to {0^ + }} f(x)\) is equal to
