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Differential Equations

JEE Main 2023 (Online) 29th January Morning Shift

MCQ+4 / -12023

Let \(y=f(x)\) be the solution of the differential equation \(y(x+1)dx-x^2dy=0,y(1)=e\). Then \(\mathop {\lim }\limits_{x \to {0^ + }} f(x)\) is equal to

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