Jee Main
Differential Equations
JEE Main 2023 (Online) 29th January Evening Shift
MCQ+4 / -12023
Let \(y=y(x)\) be the solution of the differential equation \(x{\log _e}x{{dy} \over {dx}} + y = {x^2}{\log _e}x,(x > 1)\). If \(y(2) = 2\), then \(y(e)\) is equal to
