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Differential Equations

JEE Main 2023 (Online) 29th January Evening Shift

MCQ+4 / -12023

Let \(y=y(x)\) be the solution of the differential equation \(x{\log _e}x{{dy} \over {dx}} + y = {x^2}{\log _e}x,(x > 1)\). If \(y(2) = 2\), then \(y(e)\) is equal to

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