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Differential Equations

JEE Main 2023 (Online) 25th January Evening Shift

MCQ+4 / -12023

Let \(y=y(t)\) be a solution of the differential equation \({{dy} \over {dt}} + \alpha y = \gamma {e^{ - \beta t}}\) where, \(\alpha > 0,\beta > 0\) and \(\gamma > 0\). Then \(\mathop {\lim }\limits_{t \to \infty } y(t)\)

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