Jee Main
Differential Equations
JEE Main 2023 (Online) 24th January Morning Shift
MCQ+4 / -12023
Let \(y = y(x)\) be the solution of the differential equation \({x^3}dy + (xy - 1)dx = 0,x > 0,y\left( {{1 \over 2}} \right) = 3 - \mathrm{e}\). Then y (1) is equal to
