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Differential Equations

JEE Main 2023 (Online) 24th January Morning Shift

MCQ+4 / -12023

Let \(y = y(x)\) be the solution of the differential equation \({x^3}dy + (xy - 1)dx = 0,x > 0,y\left( {{1 \over 2}} \right) = 3 - \mathrm{e}\). Then y (1) is equal to

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