Current Electricity PYQs - Last 10 Years
MHT CET / Physics / Electromagnetism / 159 recent questions
PhysicsElectromagnetism2017-2026
Practice 159 MHT CET Physics questions from Current Electricity. Use the year-wise and type-wise breakdown to prioritize recent PYQs, then continue into the question list below.
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2019-2026
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Last 10 Years Current Electricity Questions
Showing 50 of 159 filtered questions.
1Current Electricity
The potential difference $\left(V_A-V_B\right)$ between the points A and B in the given figure is
MCQ+1 / -02025
2Current Electricity
A null point is obtained at 200 cm on potentiometer wire when cell in secondary circuit is shunted by $5 \Omega$. When a resistance of $15 \Omega$ is used for shunting, null point moves to 300 cm . The internal resistance of the cell is
MCQ+1 / -02025
3Current Electricity
The reading of the ammeter in the following circuit is
MCQ+1 / -02025
4Current Electricity
Only $4 \%$ of the total current in the circuit passes through a galvanometer. If the resistance of the galvanometer is G , then the shunt resistance connected to the galvanometer is
MCQ+1 / -02025
5Current Electricity
If the length of the potentiometer wire is increased by keeping constant potential difference across the wire, then
MCQ+1 / -02025
6Current Electricity
If only $5 \%$ of the total current is to be passed through galvanometer of resistance G , then the resistance of the shunt will be
MCQ+1 / -02025
7Current Electricity
The scale of a galvanometer is divided into 160 equal divisions. The galvanometer shows full scale deflection of 16 mA and maximum voltage is 80 mV . Now the range is changed so that galvanometer reads 160 V . The required resistance to be ...
MCQ+1 / -02025
8Current Electricity
To determine the internal resistance of a cell with potentiometer, when the cell is shunted by a resistance of $5 \Omega$ the balancing length is 250 cm . When the cell is shunted by $20 \Omega$, the balancing length of potentiometer wire i...
MCQ+1 / -02025
9Current Electricity
Two cells $E_1$ and $E_2$ having equal e.m.f ' $E$ ' and internal resistances $r_1$ and $r_2\left(r_1>r_2\right)$ respectively are connected in series. This combination is connected to an external resistance ' R '. It is observed that the ...
MCQ+1 / -02025
10Current Electricity
In an ammeter, $4 \%$ of the main current is passing through the galvanometer, If shunt resistance is $5 \Omega$, then resistance of galvanometer will be
MCQ+1 / -02024
11Current Electricity
When the two known resistance ' $R$ ' and ' $S$ ' are connected in the left and right gaps of a meter bridge respectively, the null point is found at a distance ' $l_1$ ' from the zero end of a meter bridge wire. An unknown resistance ' X '...
MCQ+1 / -02024
12Current Electricity
In the following circuit, the reading in the ammeter is
MCQ+1 / -02024
13Current Electricity
Potential difference between the points A and B is nearly
MCQ+1 / -02024
14Current Electricity
Two identical galvanometers are converted into voltmeter and millivoltmeter. As compared to the series resistance of voltmeter, the series resistance of millivoltmeter will be
MCQ+1 / -02024
15Current Electricity
A potentiometer wire of length 1 m is connected in series with $495 \Omega$ resistance and 2 V battery. If $0.2 \mathrm{mV} / \mathrm{cm}$ is the potential gradient, then the resistance of the potentiometer wire is
MCQ+1 / -02024
16Current Electricity
In a meter bridge experiment, the balance point is obtained if the gaps are closed by $2 \Omega$ and $3 \Omega$. A shunt of $\mathrm{X} \Omega$ is added to $3 \Omega$ resistor to shift the null point by 22.5 cm. The value of ' $x$ ' is
MCQ+1 / -02024
17Current Electricity
In a Wheatstone's bridge, the resistances in four arms are as shown in the figure. The balancing condition of the bridge is
MCQ+1 / -02024
18Current Electricity
When a galvanometer is shunted by a resistance ' $s$ ', its current capacity increases ' $n$ ' times. If the same galvanometer is shunted by another resistance ' $s_1$ ', its capacity will increase to ' $n_1$ ' times original current. The v...
MCQ+1 / -02024
19Current Electricity
In the following circuit, a power of 50 watt is absorbed in the section AB of the circuit. The value of resistance ' $x$ ' is
MCQ+1 / -02024
20Current Electricity
The range of voltmeter of resistance ' $G$ ' $\Omega$ is ' $V$ ' volt. The resistance required to be connected in series with it in order to convert it into a voltmeter of range ' $n V$ ' volt, will be
MCQ+1 / -02024
21Current Electricity
Resistances in the left gap and right gap of a meter bridge are $10 \Omega$ and $30 \Omega$ respectively. If the resistances in the two gaps are interchanged, the balance point will shift to right by
MCQ+1 / -02024
22Current Electricity
When a galvanometer is shunted by a resistance ' $S$ ', its current capacity increases ' $n$ ' times. If the same galvanometer is shunted by another resistance $\mathrm{S}^{\prime}$, its current capacity increases to $\mathrm{n}^{\prime}$. ...
MCQ+1 / -02024
23Current Electricity
A galvanometer of resistance ' $G$ ' is shunted by resistance of 'S' ohm. To keep the main current in the circuit unchanged the resistance to be put in series with Galvanometer is
MCQ+1 / -02024
24Current Electricity
The resistances in the left and right gap of a metre bridge are $40 \Omega$ and $60 \Omega$ respectively. When the bridge is balanced, the distance of the null point from the centre of the wire towards left is
MCQ+1 / -02024
25Current Electricity
In the following circuit, the current flowing through zener diode is
MCQ+1 / -02024
26Current Electricity
In the following circuit, the current $\mathrm{I_2}$ is
MCQ+1 / -02024
27Current Electricity
When cell of E.M.F. ' $E_1$ ' is connected to potentiometer wire, the balancing length is $l_1$. Another cell of E.M.F. ' $E_2$ ' $\left(E_1>E_2\right)$ is connected so that two cells oppose each other, then the balancing length is $l_2$. T...
MCQ+1 / -02024
28Current Electricity
The current flowing in a coil is 3 A and the power consumed is 108 W . If the a.c. source is of $120 \mathrm{~V}, 50 \mathrm{~Hz}$, the resistance in the circuit is
MCQ+1 / -02024
29Current Electricity
The potential difference $\left(V_A-V_B\right)$ between the points A and B in the given part of the circuit
MCQ+1 / -02024
30Current Electricity
When a resistance of $100 \Omega$ is connected in series with a galvanometer of resistance G , its range is V . To double its range a resistance of $1000 \Omega$ is connected in series. The value of G is
MCQ+1 / -02024
31Current Electricity
When a resistance of $200 \Omega$ is connected in series with a galvanometer of resistance ' $G$ ', its range is ' $V$ '. To triple its range, a resistance of $2000 \Omega$ is connected in series. The value of ' $G$ ' is
MCQ+1 / -02024
32Current Electricity
Two identical galvanometers are converted into an ammeter and into milliammeter. For the same current, the value of shunt of the ammeter as compared to that of milliammeter is
MCQ+1 / -02024
33Current Electricity
A galvanometer has resistance $80 \Omega$ and it is shunted with resistance $20 \Omega$. If $20 \%$ of the main current flows through galvanometer, then what is the value of main current?
MCQ+1 / -02024
34Current Electricity
A cell balances against a length of 150 cm on a potentiometer wire when it is shunted by a resistance of $5 \Omega$. But when it is shunted by a resistance of $10 \Omega$, then balancing length increases by 25 cm . The balancing length when...
MCQ+1 / -02024
35Current Electricity
The figure shows currents in a part of electric circuit. Then current I is
MCQ+1 / -02024
36Current Electricity
A galvanometer may be converted into ammeter or a voltmeter. In which of the following cases the resistance of the device so obtained will be the largest?
MCQ+1 / -02024
37Current Electricity
The current drawn from the battery in the given network is (Internal resistance of the battery is negligible)
MCQ+1 / -02024
38Current Electricity
In the following electrical network, the value of I is
MCQ+1 / -02024
39Current Electricity
Kirchhoff's second law is based on the law of conservation of
MCQ+1 / -02024
40Current Electricity
A battery of 6 V is connected to the ends of uniform wire 3 m long and of resistance $100 \Omega$. The difference of potential between two points 50 cm apart on the wire is
MCQ+1 / -02024
41Current Electricity
In the circuit, current flowing through the circuit is
MCQ+1 / -02024
42Current Electricity
In potentiometer experiment, cells of e.m.f. $E_1$ and $E_2$ are connected in series $\left(E_1>E_2\right)$ the balancing length is 80 cm of the wire. If the polarity of $E_2$ is reversed, the balancing length becomes 20 cm. The ratio $\mat...
MCQ+1 / -02024
43Current Electricity
In an ammeter, $0.25 \%$ of main current passes through the galvanometer. If the resistance of the galvanometer is ' G ', the resistance of ammeter will be
MCQ+1 / -02024
44Current Electricity
The potential difference $\left(V_A-V_B\right)$ between the points ' $A$ ' and ' $B$ ' in the given part of the circuit is
MCQ+1 / -02024
45Current Electricity
In a meter bridge experiment null point is obtained at \(l \mathrm{~cm}\) from the left end. If the meter bridge wire is replaced by a wire of same material but twice the area of across-section, then the null point is obtained at a distance
MCQ+1 / -02023
46Current Electricity
A galvanometer of resistance \(\mathrm{G}\) is shunted with a resistance of \(10 \%\) of \(\mathrm{G}\). The part of the total current that flows through the galvanometer is
MCQ+1 / -02023
47Current Electricity
Five current carrying conductors meet at a point '\(\mathrm{O}\)' as shown in figure. The magnitude and direction of the current in conductor '\(O P\)' is
MCQ+1 / -02023
48Current Electricity
A galvanometer of resistance \(20 ~\Omega\) gives a deflection of 5 divisions when \(1 \mathrm{~mA}\) current flows through it. The galvanometer scale has 50 divisions. To convert the galvanometer into a voltmeter of range 25 volt, we shoul...
MCQ+1 / -02023
49Current Electricity
Five current carrying conductors meet at point \(\mathrm{P}\). What is the magnitude and direction of the current in conductor \(\mathrm{PQ}\)?
MCQ+1 / -02023
50Current Electricity
A wire of length \(3 \mathrm{~m}\) connected in the left gap of a meter-bridge balances \(8 \Omega\) resistance in the right gap at a point, which divides the bridge wire in the ratio \(3: 2\). The length of the wire corresponding to resist...
MCQ+1 / -02023
