PracBeeLogin

Current Electricity PYQs - Last 10 Years

MHT CET / Physics / Electromagnetism / 159 recent questions

PhysicsElectromagnetism2017-2026

Practice 159 MHT CET Physics questions from Current Electricity. Use the year-wise and type-wise breakdown to prioritize recent PYQs, then continue into the question list below.

159
PYQs on Page
Physics / Electromagnetism
2019-2026
Year Range
Based on indexed question metadata
120
Last 5 Years
2022-2026
159
Last 10 Years
2017-2026

Recent Year Trend

2021
2022
2023
2024
2025
2026Latest year
202135 max PYQs/year2026

Question Types

159PYQs
MCQ100%

Difficulty Mix

#1 Unknown159
120 in last 5 years159 in last 10 years

Last 10 Years Current Electricity Questions

Showing 50 of 159 filtered questions.

1Current Electricity
In the circuit shown charge q varies with time t as $q = t^2 - 5$, where q is in coulomb and t is in second. At time $t = 3$ second, voltage $V_{AB}$ in volt will be
MCQ+1 / -02026
2Current Electricity
Two cells of e.m.f. $E_1$ and $E_2$ ($E_1 > E_2$) are connected as shown in figure.
When a potentiometer is connected between points A and B the balancing length of potentiometer wire is $412$ cm. When same potentiometer wire is connected b...
MCQ+1 / -02026
3Current Electricity
In meter bridge experiment, two resistances X and Y in the two gaps give a null point dividing the wire in the ratio $2 : 3$. When each resistance is increased by $30\,\Omega$, the null point divides the wire in the ratio $5 : 6$. The resis...
MCQ+1 / -02026
4Current Electricity
The currents in different parts of the electric circuit are shown in following figure. The value of current $i$ is
MCQ+1 / -02026
5Current Electricity
Figure shows a potentiometer wire AB having resistance of $5\ \Omega$ and length 10 m. An e.m.f. is $0.4$ V of battery, the balancing length AP is (internal resistance is negligible)
MCQ+1 / -02026
6Current Electricity
In a potentiometer circuit when two cells of e.m.f. $1.5$ volt and $1.2$ volt are connected to assist each other, balancing length is $270$ cm. What will be the balancing length in cm when these two cells are connected in opposition?
MCQ+1 / -02026
7Current Electricity
In a meter bridge experiment, the balance point is obtained at length '$l_1$' cm from left hand when resistances in the left gap and right gap are $15 \ \Omega$ and $R \ \Omega$ respectively. When the resistance $R$ is shunted with equal re...
MCQ+1 / -02026
8Current Electricity
The resistances in the two gaps of a balanced meter bridge are 'X' $\Omega$ and '3X' $\Omega$ respectively. If the resistances are interchanged the balance point shifts by
MCQ+1 / -02026
9Current Electricity
By connecting a resistance of $980\ \Omega$ in series with a galvanometer, it is converted into a voltmeter of a certain range. When the resistance of $470\ \Omega$ is connected in series, the range is halved. The resistance of the galvanom...
MCQ+1 / -02026
10Current Electricity
A potentiometer wire of length $4\ \text{m}$ and resistance $5\ \Omega$ is connected in series with a resistance of $992\ \Omega$ and a cell of e.m.f. $4\ \text{V}$ with internal resistance $3\ \Omega$. The length of $0.75\ \text{m}$ on pot...
MCQ+1 / -02026
11Current Electricity
In the following network,$I_1 = -0.4\,\text{A}$ , $I_4 = 1\,\text{A}$ , $I_5 = 0.4\,\text{A}$The values of $I_2$, $I_3$ and $I_6$ are respectively
MCQ+1 / -02026
12Current Electricity
When cell of E.M.F. '$E_1$' is connected to potentiometer wire the balancing length is '$l_1$'. Another cell of E.M.F. '$E_2$' ($E_1 > E_2$) is connected along with $E_1$ so as two cells oppose each other, the balancing length is '$l_2$'. T...
MCQ+1 / -02026
13Current Electricity
With a resistance '$X$' connected in series with a galvanometer of resistance $100\ \Omega$, it acts as a voltmeter of range 0 - 15 V. To double the range, a resistance of $1500\ \Omega$ is to be connected in series with '$X$'. The value of...
MCQ+1 / -02026
14Current Electricity
In the following figure, the current I is equal to
MCQ+1 / -02026
15Current Electricity
A current of 9A enters point P of an equilateral triangle PQR having three wires of $3\Omega$ each and leaves by point R. The currents $I_1$ and $I_2$ are respectively
MCQ+1 / -02026
16Current Electricity
A metre bridge experiment, the resistance in the left gap is $20\ \Omega$ and in the right gap is $60\ \Omega$. The bridge is balanced. The distance of the null point from the centre of the wire is
MCQ+1 / -02026
17Current Electricity
A potentiometer wire is 4m long and potential difference of 3V is maintained between the ends. The e.m.f. of the cell which balances against a length of 100 cm of the potentiometer wire is
MCQ+1 / -02026
18Current Electricity
If the potential difference between points B and D is zero in the given circuit, the value of x is $\dfrac{1}{n}\ \Omega$. The value n is
MCQ+1 / -02026
19Current Electricity
A potentiometer wire is 4m long and potential difference of 2V is maintained between the ends. The e.m.f. of the cell which balances against a length of 80 cm of the potentiometer wire is
MCQ+1 / -02026
20Current Electricity
In metre bridge experiment, the resistance in the left gap is 15 $\Omega$ and in the right gap is 45 $\Omega$. The bridge is balanced. The distance of the null point from the centre of the wire is
MCQ+1 / -02026
21Current Electricity
Which of the following graph represents the temperature (T) dependence of resistivity ($\rho$) of a semiconductor?
MCQ+1 / -02026
22Current Electricity
Two wires A and B of equal lengths are connected in left and right gap respectively of a metre bridge, null point is obtained at 40 cm from left end. Diameters of the wires A and B are in the ratio 3:1 respectively, the ratio of specific re...
MCQ+1 / -02026
23Current Electricity
A potentiometer wire is 4 m long and potential difference of 3V is maintained between the ends. The e.m.f. of the cell which balances against a length of 100 cm of the poteniometer wire is
MCQ+1 / -02026
24Current Electricity
In an experiment to find emf of a cell using potentiometer, the length of null point for a cell of emf $1.5$ V is found to be $60$ cm. If this cell is replaced by another cell of emf $E$, the length of null point increases by $40$ cm. The v...
MCQ+1 / -02026
25Current Electricity
Resistances are joint as shown in the figure. In the balanced condition, the current $I$ drawn from the battery is
MCQ+1 / -02026
26Current Electricity
In a metre bridge experiment the balance point is obtained if the gaps are closed by $2$ $\Omega$ and $3\Omega$. A shunt of $X$ $\Omega$ is added to $3$ $\Omega$ resistor to shift the balancing point by $22.5$ cm. The value of $X$ is
MCQ+1 / -02026
27Current Electricity
In the following network, the current flowing through $15\ \Omega$ resistance is
MCQ+1 / -02026
28Current Electricity
In potentiometer experiment, null point is obtained at a particular point for a cell on potentiometer wire 'x' cm long. If length of potentiometer wire is increased by few cm without changing the cell, the balancing length will (Driving sou...
MCQ+1 / -02026
29Current Electricity
A 2.5 V battery is connected to a potentiometer wire. A cell of e.m.f. 1.08 V is balanced by the voltage drop across 2.16 m of wire. The length of the potentiometer wire is
MCQ+1 / -02025
30Current Electricity
In metre-bridge experiment the balance point is obtained if the gaps are closed by $2 \Omega$ and $3 \Omega$. A shunt of $\mathrm{x} \Omega$ is added to $3 \Omega$ resistor to shift the balance point by 22.5 cm . The value of x is
MCQ+1 / -02025
31Current Electricity
The potentiometer wire is 5 m long and potential difference of 4 V is maintained between the ends. The e.m.f. of the cell which balances against a length of 200 cm of the potentiometer wire is
MCQ+1 / -02025
32Current Electricity
When a resistance of $100 \Omega$ is connected in series with a galvanometer of resistance ' G ', its range is ' $V$ '. To double its range, a resistance of $1000 \Omega$ is connected in series. The value of ' $G$ ' is
MCQ+1 / -02025
33Current Electricity
In the following circuit, current through ACB if each resistance $\mathrm{R}=4 \Omega$ is
MCQ+1 / -02025
34Current Electricity
Kirchhoff's voltage law and current law are based (respectively) on the conservation of
MCQ+1 / -02025
35Current Electricity
The current (I) drawn from the battery in the given circuit is
MCQ+1 / -02025
36Current Electricity
The value of the shunt resistance that allows $10 \%$ of the main current through the galvanometer of $99 \Omega$ is
MCQ+1 / -02025
37Current Electricity
Two batteries of e.m.f 4 V and 8 V with internal resistance $1 \Omega$ and $2 \Omega$ respectively are connected in a circuit with a resistance of $9 \Omega$ as shown in the figure. The current and potential difference between the points ' ...
MCQ+1 / -02025
38Current Electricity
With a resistance ' X ' connected in series with a galvanometer of resistance $100 \Omega$, it acts as a voltmeter of range $0-15 \mathrm{~V}$. To double the range, a resistance of $1500 \Omega$ is to be connected in series with ' X '. The ...
MCQ+1 / -02025
39Current Electricity
In the following circuit, the current through $6 \Omega$ resistor is
MCQ+1 / -02025
40Current Electricity
The equivalent resistance of the following circuit when no current flows in the resistance of $5 \Omega$ is nearly
MCQ+1 / -02025
41Current Electricity
Two cells of e.m.f.s $E_1$ and $E_2\left(E_1>E_2\right)$ are connected as shown in figure.
When the potentiometer is connected between A and B , the balancing length of the potentiometer wire is 3.60 m . On connecting the potentiometer betw...
MCQ+1 / -02025
42Current Electricity
The length of a potentiometer wire is ' $L$ '. A cell of e.m.f. ' $E$ ' is balanced at a length $\frac{L}{4}$ from the positive end of the wire. If the length of the original wire is increased by $\frac{\mathrm{L}}{3}$, then using the same ...
MCQ+1 / -02025
43Current Electricity
In the given electrical network, the value of resistance ' $R$ ' when the current in the galvanometer will be zero, is
MCQ+1 / -02025
44Current Electricity
The voltmeter has range 10 V and its internal resistance is $50 \Omega$. To increase the range of voltmeter to 15 V , the resistance which is to be connected is
MCQ+1 / -02025
45Current Electricity
When cell of e.m.f. ' $E_1$ ' is connected to potentiometer wire, the balancing length is ' $l_l$ '. Another cell of e.m.f. ' $E_2$ ' $\left(E_1>E_2\right)$ is connected so that two cells oppose each other, the balancing length is ' $l_1$ '...
MCQ+1 / -02025
46Current Electricity
In the given circuit, current flowing through the circuit is
MCQ+1 / -02025
47Current Electricity
\(\text { The value of current I in the given circuit is }\)
MCQ+1 / -02025
48Current Electricity
The length of a potentiometer wire is ' $L$ ' . A cell of e.m.f. $E$ is balanced at a length $\frac{L}{5}$ from the positive end of the wire. If the length of the wire is increased by $\frac{L}{2}$, the same cell will give balance point at ...
MCQ+1 / -02025
49Current Electricity
In the circuit shown in the figure, $P \neq R$. The reading of the galvanometer remains the same with switch ' $S$ ' open or closed. Then
MCQ+1 / -02025
50Current Electricity
If an ammeter is to be used in place of a galvanometer then we must connect
MCQ+1 / -02025