Jee Main
Differential Equations
JEE Main 2026 (Online) 4th April Morning Shift
MCQ+4 / -12026
Let $y=y(x)$ be the solution of the differential equation $\frac{d y}{d x}=\left(1+x+x^2\right)\left(1-y+y^2\right), y(0)=\frac{1}{2}$. Then $(2 y(1)-1)$ is equal to