Jee Main
Differential Equations
JEE Main 2026 (Online) 2nd April Morning Shift
MCQ+4 / -12026
Let $y = y(x)$ be the solution curve of the differential equation
$(1 + \sin x)\dfrac{dy}{dx} + (y + 1)\cos x = 0,\ y(0) = 0.$ If the curve $y = y(x)$ passes through the point $\left( \alpha , \dfrac{-1}{2} \right)$,
then a value of $\alpha$ is:
