Jee Main
Differential Equations
JEE Main 2026 (Online) 2nd April Evening Shift
MCQ+4 / -12026
Let $x = x(y)$ be the solution of the differential equation $2y^2 \frac{dx}{dy} - 2xy + x^2 = 0$, $y > 1$, $x(e) = e$.
Then $x(e^2)$ is equal to:
Jee Main
JEE Main 2026 (Online) 2nd April Evening Shift
Let $x = x(y)$ be the solution of the differential equation $2y^2 \frac{dx}{dy} - 2xy + x^2 = 0$, $y > 1$, $x(e) = e$.
Then $x(e^2)$ is equal to: