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JEE Main 2025 (Online) 4th April Evening Shift

MCQ+4 / -12025

Displacement of a wave is expressed as $x(t)=5 \cos \left(628 t+\frac{\pi}{2}\right) \mathrm{m}$. The wavelength of the wave when its velocity is $300 \mathrm{~m} / \mathrm{s}$ is :


\((\pi=3.14)\)

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