Jee Main
Alternating Current
JEE Main 2025 (Online) 24th January Morning Shift
MCQ+4 / -12025
An alternating current is given by $\mathrm{I}=\mathrm{I}_{\mathrm{A}} \sin \omega \mathrm{t}+\mathrm{I}_{\mathrm{B}} \cos \omega \mathrm{t}$. The r.m.s current will be