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Laws Of Motion

JEE Main 2024 (Online) 9th April Evening Shift

MCQ+4 / -12024

A \(1 \mathrm{~kg}\) mass is suspended from the ceiling by a rope of length \(4 \mathrm{~m}\). A horizontal force '\(F\)' is applied at the mid point of the rope so that the rope makes an angle of \(45^{\circ}\) with respect to the vertical axis as shown in figure. The magnitude of \(F\) is :


(Assume that the system is in equilibrium and \(g=10 \mathrm{~m} / \mathrm{s}^2\))


JEE Main 2024 (Online) 9th April Evening Shift Physics - Laws of Motion Question 34 English

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