16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T4e6,{"@context":"https://schema.org","@type":"Quiz","name":"Jee Main 2023 Wave Optics PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/jee-main/questions/2023/physics/wave-optics/1lgyqx612","educationalLevel":"Entrance exam preparation","about":"Jee Main / Physics / Wave Optics","hasPart":{"@type":"Question","name":"Jee Main 2023 Wave Optics PYQ with Solution","text":"The width of fringe is 2 \\mathrm{~mm} on the screen in a double slits experiment for the light of wavelength of 400 \\mathrm{~nm}. The width of the fringe for the light of wavelength 600 \\mathrm{nm} will be:","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"D"},"comment":{"@type":"Comment","text":"In the double-slit experiment, the fringe width (\\beta) is given by the formula : \\beta = \\frac{\\lambda D}{d} where: \\lambda is the wavelength of the light, D is the distance between the screen and the double-slit, d is the separation between the two slits. If we are considering a change in wavelength but the fringe width is changing and the setup of the experiment (the values of D and d) stays the same, we can see that the fringe width is directly proportional to the wavelength. This is becaus..."}}}18:T534,

In the double-slit experiment, the fringe width ($\beta$) is given by the formula :

$ \beta = \frac{\lambda D}{d} $

where:

$\lambda$ is the wavelength of the light,
$D$ is the distance between the screen and the double-slit,
$d$ is the se

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