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Differential Equations

JEE Main 2022 (Online) 27th June Evening Shift

MCQ+4 / -12022

If the solution curve of the differential equation

\((({\tan ^{ - 1}}y) - x)dy = (1 + {y^2})dx\) passes through the point (1, 0), then the abscissa of the point on the curve whose ordinate is tan(1), is

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