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Differential Equations

JEE Main 2022 (Online) 26th June Evening Shift

MCQ+4 / -12022

If the solution of the differential equation

\({{dy} \over {dx}} + {e^x}\left( {{x^2} - 2} \right)y = \left( {{x^2} - 2x} \right)\left( {{x^2} - 2} \right){e^{2x}}\) satisfies \(y(0) = 0\), then the value of y(2) is _______________.

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