Wb Jee
Limits Continuity And Differentiability
WB JEE 2024
MCQ+1 / -0.252024
\(a x^2+b x+c=0\) সমীকরণের বীজদ্বয় \(\alpha\) ও \(\beta\) হলে \(\lim _\limits{x \rightarrow \beta} \frac{1-\cos \left(a x^2+b x+c\right)}{(x-\beta)^2}\) এর মান হবে
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