Mht CetProperties Of TrianglesMHT CET 2026 15th April Morning ShiftMCQ+2 / -02026In $\triangle ABC$, with the usual notations, $\angle C = 90^\circ$, then $\sin(A - B)$ is equal to....A$\dfrac{a^2 + b^2}{a^2 - b^2}$B$\dfrac{a^2 + c^2}{a^2 - c^2}$C$\dfrac{b^2 + c^2}{b^2 - c^2}$D$\dfrac{a^2 - b^2}{a^2 + b^2}$Check AnswerClear SelectionReveal AnswerShow Explanation
