Mht CetProperties Of TrianglesMHT CET 2026 13th April Morning ShiftMCQ+2 / -02026With usual notations, in $\triangle ABC$, $(b - c)^2 \cos^2 \dfrac{A}{2} + (b + c)^2 \sin^2 \dfrac{A}{2} =$A$a^2$B$b^2 - c^2$C$a^2 + b^2 + c^2$D$0$Check AnswerClear SelectionReveal AnswerShow Explanation
