Mht CetProperties Of TrianglesMHT CET 2026 13th April Morning ShiftMCQ+2 / -02026With usual notations, in $\triangle ABC$, if $2a^2 = b^2 + c^2$, then $\dfrac{\cos 3A}{\cos A} + 2 =$A$\dfrac{b^2 - c^2}{2bc}$B$\left(\dfrac{b^2 - c^2}{2bc}\right)^2$C$\left(\dfrac{c^2 - b^2}{bc}\right)^2$D$\dfrac{c^2 - b^2}{bc}$Check AnswerClear SelectionReveal AnswerShow Explanation
