Mht CetDifferential EquationsMHT CET 2026 13th April Evening ShiftMCQ+2 / -02026The general solution of the differential equation $(x+y)\dfrac{dy}{dx} = 1$ isA$x + y + 1 = c$, where $c$ is a constant of integrationB$x + y + 1 = ce^y$, where $c$ is a constant of integrationC$x + y + 1 = ce^{-y}$, where $c$ is a constant of integrationD$x + y - 1 = ce^{-y}$, where $c$ is a constant of integrationCheck AnswerClear SelectionReveal AnswerShow Explanation
