Mht CetDifferential EquationsMHT CET 2026 13th April Evening ShiftMCQ+2 / -02026The differential equation of $3y = \sqrt[3]{x+c}$ isA$\dfrac{dy}{dx} = \dfrac{1}{9y^2}$B$\dfrac{dy}{dx} = \dfrac{1}{27y^2}$C$\dfrac{dy}{dx} = \dfrac{1}{81y^2}$D$\dfrac{dy}{dx} = \dfrac{1}{36y^2}$Check AnswerClear SelectionReveal AnswerShow Explanation
