Mht CetDifferential EquationsMHT CET 2026 11th April Evening ShiftMCQ+2 / -02026The solution of the differential equation $x\dfrac{dy}{dx} + y = x^3 y^6$, is...A$y^5 = \dfrac{5}{2}x^{-3} + cx^5$B$y^5 = \dfrac{5}{2}x^3 + cx^5$C$\dfrac{1}{y^5} = \dfrac{5}{2}x^{-3} + cx^5$D$\dfrac{1}{y^5} = \dfrac{5}{2}x^3 + cx^5$Check AnswerClear SelectionReveal AnswerShow Explanation
