Mht CetArea Under The CurvesMHT CET 2026 17th April Evening ShiftMCQ+2 / -02026The area of the region bounded by curves $y = \sin x, y = \cos x$ and the lines $x = 0$, $x = \dfrac{\pi}{4}$ isA$2\sqrt{2} - 1$B$\sqrt{2} - 1$C$2 - \sqrt{2}$D$\dfrac{1 - \sqrt{2}}{2}$Check AnswerClear SelectionReveal AnswerShow Explanation
