Mht CetArea Under The CurvesMHT CET 2026 15th April Morning ShiftMCQ+2 / -02026The area of the smaller region bounded by the circle $x^2 + y^2 = 4$ and the line $x = 1$ is...A$\dfrac{4\pi}{3} - \sqrt{3}$B$\dfrac{\pi}{3} - \sqrt{3}$C$\dfrac{4\pi}{3} + \sqrt{3}$D$\dfrac{\pi}{3} + \sqrt{3}$Check AnswerClear SelectionReveal AnswerShow Explanation
