Mht CetArea Under The CurvesMHT CET 2026 19th April Evening ShiftMCQ+2 / -02026The area (in square units) of the region bounded by the circle $x^2 + y^2 = 9$ and the parabola $y^2 \leq 8x$ is...A$\dfrac{8\sqrt{2}}{3} + \dfrac{9\pi}{2} - 2\sqrt{2} - 9\sin^{-1}\dfrac{1}{3}$B$\dfrac{8\sqrt{2}}{3} + \dfrac{9\pi}{2} + 2\sqrt{2} + 9\sin^{-1}\dfrac{1}{3}$C$\dfrac{4\sqrt{2}}{3} + \dfrac{9\pi}{4} - \sqrt{2} - \dfrac{9}{2}\sin^{-1}\dfrac{1}{3}$D$\dfrac{4\sqrt{2}}{3} + \dfrac{9\pi}{4} + \sqrt{2} + \dfrac{9}{2}\sin^{-1}\dfrac{1}{3}$Check AnswerClear SelectionReveal AnswerShow Explanation
