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Kcet

Differentiation

KCET 2021

MCQ+1 / -02021

Consider the following statements


Statement 1 : If \(y=\log _{10} x+\log _e x\), then \(\frac{d y}{d x}=\frac{\log _{10} e}{x}+\frac{1}{x}\)


Statement 2 : If \(\frac{d}{d x}\left(\log _{10} x\right)=\frac{\log x}{\log 10}\) and \(\frac{d}{d x}\left(\log _e x\right)=\frac{\log x}{\log e}\)

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