KcetDifferentiationKCET 2019MCQ+1 / -02019\(\sqrt[3]{y} \sqrt{x}=\sqrt[6]{(x+y)^5}\), then \(\frac{d y}{d x}=\)A\(x-y\)B\(\frac{x}{y}\)C\(\frac{y}{x}\)D\(x+y\)Check AnswerClear SelectionReveal AnswerShow Explanation
