KcetDifferentiationKCET 2026MCQ+1 / -02026If $f(x) = \sin^{-1}\left(\dfrac{2x}{1 + x^2}\right)$, then $f'\left(\dfrac{1}{2}\right) = $A$\dfrac{8}{5}$B$\dfrac{5}{8}$C$\dfrac{4}{5}$D$0$Check AnswerClear SelectionReveal AnswerShow Explanation
