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Differentiation

KCET 2025

MCQ+1 / -02025

If $y=\frac{\cos x}{1+\sin x}$, then


(a) $\frac{d y}{d x}=\frac{-1}{1+\sin x}$


(b) $\frac{d y}{d x}=\frac{1}{1+\sin x}$


(c) $\frac{\mathrm{dy}}{\mathrm{dx}}=-\frac{1}{2} \sec ^2\left(\frac{\pi}{4}-\frac{\mathrm{x}}{2}\right)$


(d) $\frac{\mathrm{dy}}{\mathrm{dx}}=\frac{1}{2} \sec ^2\left(\frac{\pi}{4}-\frac{\mathrm{x}}{2}\right)$

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