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KCET 2019

MCQ+1 / -02019

A random variable '\(X\)' has the following probability distribution



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\(x\) \(1\) \(2\) \(3\) \(4\) \(5\) \(6\) \(7\)
\(P(x)\) \(k-1\) \(3k\) \(k\) \(3k\) \(3k^2\) \(k^2\) \(k^2+k\)


Then the value of \(k\) is

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