Kcet
Probability
KCET 2026
MCQ+1 / -02026
Recent studies suggest that $12\%$ of the world population is left handed. Depending on parents' hand usage, the chances of having left handed children are as follows:
A: Both parents are left handed, chances of having left handed children $= 24\%$
B: Both parents are right handed, chances of having left handed children $= 9\%$
C: Father left handed and mother right handed, chances of having left handed children $= 17\%$
D: Father right handed and mother left handed, chances of having left handed children $= 22\%$
Given $P(A) = P(B) = P(C) = P(D) = 1/4$ and L denotes child is left handed. What is the probability that $P(A \mid L)$?
A: Both parents are left handed, chances of having left handed children $= 24\%$
B: Both parents are right handed, chances of having left handed children $= 9\%$
C: Father left handed and mother right handed, chances of having left handed children $= 17\%$
D: Father right handed and mother left handed, chances of having left handed children $= 22\%$
Given $P(A) = P(B) = P(C) = P(D) = 1/4$ and L denotes child is left handed. What is the probability that $P(A \mid L)$?