16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T4d3,{"@context":"https://schema.org","@type":"Quiz","name":"Kcet 2018 Probability PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/kcet/questions/2018/mathematics/probability/m7isgtj1","educationalLevel":"Entrance exam preparation","about":"Kcet / Mathematics / Probability","hasPart":{"@type":"Question","name":"Kcet 2018 Probability PYQ with Solution","text":"A bag contains 17 tickets numbered from 1 to 17. A ticket is drawn at random, then another ticket is drawn without replacing the first one. The probability that both the tickets may show even numbers is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"A"},"comment":{"@type":"Comment","text":"Let's break down the problem step by step: The tickets are numbered from 1 to 17. The even numbers within this range are: 2, 4, 6, 8, 10, 12, 14, and 16. There are 8 even-numbered tickets. Now, when drawing two tickets without replacement, the probability that both are even can be calculated as follows: Probability of drawing an even ticket first: P(\\text{first even}) = \\frac{8}{17} Probability of drawing an even ticket second (after one even is already drawn): Now there are 7 even tickets left..."}}}18:T4e1,

Let's break down the problem step by step:

The tickets are numbered from 1 to 17.

The even numbers within this range are: 2, 4, 6, 8, 10, 12, 14, and 16. There are 8 even-numbered tickets.

Now, when drawing two tickets without replacement, the probability that bo

Probability

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