KcetMoving Charges And MagnetismKCET 2018MCQ+1 / -02018The correct Biot-Savart law in vector form isA$d \mathbf{B}=\frac{\mu_0}{4 \pi} \cdot \frac{l(d \mathbf{} \times \mathbf{r})}{r^2}$B$d \mathbf{B}=\frac{\mu_0}{4 \pi} \cdot \frac{\mid(d \mathbf{} \mathbf{~} \times \mathbf{r})}{r^3}$C$d \mathbf{B}=\frac{\mu_0}{4 \pi} \cdot \frac{|d|}{r^2}$D$d \mathbf{B}=\frac{\mu_0}{4 \pi} \cdot \frac{|d|}{r^3}$Check AnswerClear SelectionReveal AnswerShow Explanation
