KcetElectrochemistryKCET 2018MCQ+1 / -02018For a cell involving two electron changes, $E_{\text {cell }}^{\circ}=03 \mathrm{~V}$ at $25^{\circ} \mathrm{C}$. The equilibrium constant of the reaction isA$10^{-10}$B$3 \times 10^{-2}$C10D$10^{10}$Check AnswerClear SelectionReveal AnswerShow Explanation
