KcetElectrochemistryKCET 2026MCQ+1 / -02026$\Lambda^0_{m(\text{NH}_4\text{OH})}$ is equal to ____A$\Lambda^0_{m(\text{NH}_4\text{OH})} + \Lambda^0_{m(\text{NH}_4\text{Cl})} - \Lambda^0_{m(\text{HCl})}$B$\Lambda^0_{m(\text{NH}_4\text{Cl})} + \Lambda^0_{m(\text{NaOH})} - \Lambda^0_{m(\text{NaCl})}$C$\Lambda^0_{m(\text{NH}_4\text{Cl})} + \Lambda^0_{m(\text{NaCl})} - \Lambda^0_{m(\text{NaOH})}$D$\Lambda^0_{m(\text{NaOH})} + \Lambda^0_{m(\text{NaCl})} - \Lambda^0_{m(\text{NH}_4\text{Cl})}$Check AnswerClear SelectionReveal AnswerShow Explanation
