Kcet
Electrochemistry
KCET 2026
MCQ+1 / -02026
Given below are the half-cell reactions:
$\text{Mn}^{2+} + 2e^- \rightarrow \text{Mn} \quad (E^0 = -1.18\text{ V})$
$2(\text{Mn}^{3+} + e^- \rightarrow \text{Mn}^{2+}) \quad (E^0 = +1.51\text{ V})$
The $E^0_{cell}$ for $3\text{Mn}^{2+} \rightarrow \text{Mn} + 2\text{Mn}^{3+}$ will be _____________.
$\text{Mn}^{2+} + 2e^- \rightarrow \text{Mn} \quad (E^0 = -1.18\text{ V})$
$2(\text{Mn}^{3+} + e^- \rightarrow \text{Mn}^{2+}) \quad (E^0 = +1.51\text{ V})$
The $E^0_{cell}$ for $3\text{Mn}^{2+} \rightarrow \text{Mn} + 2\text{Mn}^{3+}$ will be _____________.