Chemical Equilibrium PYQs - Last 5 Years
JEE Main / Chemistry / Physical Chemistry / 59 recent questions
ChemistryPhysical Chemistry2022-2026
Practice 59 JEE Main Chemistry questions from Chemical Equilibrium. Use the year-wise and type-wise breakdown to prioritize recent PYQs, then continue into the question list below.
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59 in last 5 years59 in last 10 years
Last 5 Years Chemical Equilibrium Questions
Showing 9 of 59 filtered questions.
1Chemical Equilibrium
4.0 moles of argon and 5.0 moles of PCl5 are introduced into an evacuated flask of 100 litre capacity at 610 K. The system is allowed to equilibrate. At equilibrium, the total pressure of mixture was found to be 6.0 atm. The Kp for the reac...
MCQ+4 / -12022
2Chemical Equilibrium
At \(600 \mathrm{~K}, 2 \mathrm{~mol}\) of \(\mathrm{NO}\) are mixed with \(1 \mathrm{~mol}\) of \(\mathrm{O}_{2}\).
\(2 \mathrm{NO}_{(\mathrm{g})}+\mathrm{O}_{2}(\mathrm{g}) \rightleftarrows 2 \mathrm{NO}_{2}(\mathrm{g})\)
The reaction occ...
\(2 \mathrm{NO}_{(\mathrm{g})}+\mathrm{O}_{2}(\mathrm{g}) \rightleftarrows 2 \mathrm{NO}_{2}(\mathrm{g})\)
The reaction occ...
INTEGER+4 / -12022
3Chemical Equilibrium
2NOCl(g) \(\rightleftharpoons\) 2NO(g) + Cl2(g)
In an experiment, 2.0 moles of NOCl was placed in a one-litre flask and the concentration of NO after equilibrium established, was found to be 0.4 mol/L. The equilibrium constant at 30$$^\circ...
In an experiment, 2.0 moles of NOCl was placed in a one-litre flask and the concentration of NO after equilibrium established, was found to be 0.4 mol/L. The equilibrium constant at 30$$^\circ...
INTEGER+4 / -12022
4Chemical Equilibrium
40% of HI undergoes decomposition to H2 and I2 at 300 K. \(\Delta\)G\(^\Theta\) for this decomposition reaction at one atmosphere pressure is __________ J mol\(-\)1. [nearest integer]
(Use R = 8.31 J K\(-\)1 mol\(-\)1 ; log 2 = 0.3010, ln ...
(Use R = 8.31 J K\(-\)1 mol\(-\)1 ; log 2 = 0.3010, ln ...
INTEGER+4 / -12022
5Chemical Equilibrium
At \(298 \mathrm{~K}\), the equilibrium constant is \(2 \times 10^{15}\) for the reaction :
\(\mathrm{Cu}(\mathrm{s})+2 \mathrm{Ag}^{+}(\mathrm{aq}) \rightleftharpoons \mathrm{Cu}^{2+}(\mathrm{aq})+2 \mathrm{Ag}(\mathrm{s})\)
The equilibriu...
\(\mathrm{Cu}(\mathrm{s})+2 \mathrm{Ag}^{+}(\mathrm{aq}) \rightleftharpoons \mathrm{Cu}^{2+}(\mathrm{aq})+2 \mathrm{Ag}(\mathrm{s})\)
The equilibriu...
INTEGER+4 / -12022
6Chemical Equilibrium
The standard free energy change (\(\Delta\)G\(^\circ\)) for 50% dissociation of N2O4 into NO2 at 27\(^\circ\)C and 1 atm pressure is \(-\) x J mol\(-\)1. The value of x is ___________. (Nearest Integer)
[Given : R = 8.31 J K\(-\)1 mol\(-\)1...
[Given : R = 8.31 J K\(-\)1 mol\(-\)1...
INTEGER+4 / -12022
7Chemical Equilibrium
2O3(g) \(\rightleftharpoons\) 3O2(g)
At 300 K, ozone is fifty percent dissociated. The standard free energy change at this temperature and 1 atm pressure is (\(-\)) ____________ J mol\(-\)1. (Nearest integer)
[Given : ln 1.35 = 0.3 and R = ...
At 300 K, ozone is fifty percent dissociated. The standard free energy change at this temperature and 1 atm pressure is (\(-\)) ____________ J mol\(-\)1. (Nearest integer)
[Given : ln 1.35 = 0.3 and R = ...
INTEGER+4 / -12022
8Chemical Equilibrium
For a reaction at equilibrium
A(g) \(\rightleftharpoons\) B(g) + \({1 \over 2}\) C(g)
the relation between dissociation constant (K), degree of dissociation (\(\alpha\)) and equilibrium pressure (p) is given by :
A(g) \(\rightleftharpoons\) B(g) + \({1 \over 2}\) C(g)
the relation between dissociation constant (K), degree of dissociation (\(\alpha\)) and equilibrium pressure (p) is given by :
MCQ+4 / -12022
9Chemical Equilibrium
PCl5 dissociates as
PCl5(g) \(\rightleftharpoons\) PCl3(g) + Cl2(g)
5 moles of PCl5 are placed in a 200 litre vessel which contains 2 moles of N2 and is maintained at 600 K. The equilibrium pressure is 2.46 atm. The equilibrium constant Kp ...
PCl5(g) \(\rightleftharpoons\) PCl3(g) + Cl2(g)
5 moles of PCl5 are placed in a 200 litre vessel which contains 2 moles of N2 and is maintained at 600 K. The equilibrium pressure is 2.46 atm. The equilibrium constant Kp ...
INTEGER+4 / -12022