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JEE Main 2026 (Online) 28th January Evening Shift

MCQ+4 / -12026

The probability distribution of a random variable X is given below :

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X4k$\frac{30}{7}k$$\frac{32}{7}k$$\frac{34}{7}k$$\frac{36}{7}k$$\frac{38}{7}k$$\frac{40}{7}k$6k
P(X)$\frac{2}{15}$$\frac{1}{15}$$\frac{2}{15}$$\frac{1}{5}$$\frac{1}{15}$$\frac{2}{15}$$\frac{1}{5}$$\frac{1}{15}$

If E(X) = $\frac{263}{15}$, then P(X < 20) is equal to :

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