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Electrostatics

JEE Main 2025 (Online) 7th April Morning Shift

MCQ+4 / -12025

If $\epsilon_0$ denotes the permittivity of free space and $\Phi_E$ is the flux of the electric field through the area bounded by the closed surface, then dimensions of $\left(\epsilon_0 \frac{d \phi_E}{d t}\right)$ are that of :

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