Jee Main
Electrostatics
JEE Main 2026 (Online) 6th April Evening Shift
MCQ+4 / -12026
The electric potential as a function of $x, y$ is given by $V=5\left(x^2-y^2\right) V$. The electric field at a point $(2,3) \mathrm{m}$ is $\_\_\_\_$ $\mathrm{V} / \mathrm{m}$.
