Jee Main
Differential Equations
JEE Main 2025 (Online) 3rd April Evening Shift
MCQ+4 / -12025
Let $y=y(x)$ be the solution of the differential equation
$\frac{d y}{d x}+3\left(\tan ^2 x\right) y+3 y=\sec ^2 x, y(0)=\frac{1}{3}+e^3$. Then $y\left(\frac{\pi}{4}\right)$ is equal to :
