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Differential Equations

JEE Main 2025 (Online) 29th January Morning Shift

MCQ+4 / -12025

Let y = y(x) be the solution of the differential equation :


$\cos x\left(\log _e(\cos x)\right)^2 d y+\left(\sin x-3 y \sin x \log _e(\cos x)\right) d x=0$, x ∈ (0, $\frac{\pi}{2}$ ). If $ y(\frac{\pi}{4}) $ = $-\frac{1}{\log_{e}2}$, then $ y(\frac{\pi}{6}) $ is equal to :

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