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JEE Main 2024 (Online) 6th April Evening Shift

MCQ+4 / -12024

The number of electrons flowing per second in the filament of a \(110 \mathrm{~W}\) bulb operating at \(220 \mathrm{~V}\) is : (Given \(\mathrm{e}=1.6 \times 10^{-19} \mathrm{C}\))

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