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JEE Main 2024 (Online) 8th April Evening Shift

MCQ+4 / -12024

A capacitor has air as dielectric medium and two conducting plates of area \(12 \mathrm{~cm}^2\) and they are \(0.6 \mathrm{~cm}\) apart. When a slab of dielectric having area \(12 \mathrm{~cm}^2\) and \(0.6 \mathrm{~cm}\) thickness is inserted between the plates, one of the conducting plates has to be moved by \(0.2 \mathrm{~cm}\) to keep the capacitance same as in previous case. The dielectric constant of the slab is : (Given \(\epsilon_0=8.834 \times 10^{-12} \mathrm{~F} / \mathrm{m}\))

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