Jee Main
Differential Equations
JEE Main 2024 (Online) 8th April Evening Shift
MCQ+4 / -12024
Let \(y=y(x)\) be the solution curve of the differential equation \(\sec y \frac{\mathrm{d} y}{\mathrm{~d} x}+2 x \sin y=x^3 \cos y, y(1)=0\). Then \(y(\sqrt{3})\) is equal to:
