Jee Main
Differential Equations
JEE Main 2024 (Online) 4th April Morning Shift
MCQ+4 / -12024
If the solution \(y=y(x)\) of the differential equation \((x^4+2 x^3+3 x^2+2 x+2) \mathrm{d} y-(2 x^2+2 x+3) \mathrm{d} x=0\) satisfies \(y(-1)=-\frac{\pi}{4}\), then \(y(0)\) is equal to :
