Jee Main
Differential Equations
JEE Main 2024 (Online) 31st January Evening Shift
MCQ+4 / -12024
The temperature \(T(t)\) of a body at time \(t=0\) is \(160^{\circ} \mathrm{F}\) and it decreases continuously as per the differential equation \(\frac{d T}{d t}=-K(T-80)\), where \(K\) is a positive constant. If \(T(15)=120^{\circ} \mathrm{F}\), then \(T(45)\) is equal to
