Jee Main
Differential Equations
JEE Main 2024 (Online) 30th January Morning Shift
MCQ+4 / -12024
Let \(y=y(x)\) be the solution of the differential equation \(\sec x \mathrm{~d} y+\{2(1-x) \tan x+x(2-x)\} \mathrm{d} x=0\) such that \(y(0)=2\). Then \(y(2)\) is equal to:
