Wave Optics

Given below are two statements :

Statement I : If the Brewster's angle for the light propagating from air to glass is \(\mathrm{\theta_B}\), then the Brewster's angle for the light propagating from glass to air is \(\frac{\pi}{2}-\theta_B\)

Statement II : The Brewster's angle for the light propagating from glass to air is \({\tan ^{ - 1}}({\mu _\mathrm{g}})\) where \(\mathrm{\mu_g}\) is the refractive index of glass.

In the light of the above statements, choose the correct answer from the options given below :