3d Geometry

Let the plane $P$ contain the line $2 x+y-z-3=0=5 x-3 y+4 z+9$ and be

parallel to the line $\frac{x+2}{2}=\frac{3-y}{-4}=\frac{z-7}{5}$. Then the distance of the point

$\mathrm{A}(8,-1,-19)$ from the plane $\mathrm{P}$ measured parallel to the line $\frac{x}{-3}=\frac{y-5}{4}=\frac{2-z}{-12}$

is equal to ______________.